Odpowiedź :
mC2H5COOH=3*12 u+6*1 u+2*16 u=74 u
36 u---x%
74 u---100%
x=48,65%C
6 u---x%
74 u---100%
x=8,11%H
100%-(48,65%+8,11%)=%O
%O=43,24%
mC2H5COOH=3*12 u+6*1 u+2*16 u=74 u
36 u---x%
74 u---100%
x=48,65%C
6 u---x%
74 u---100%
x=8,11%H
100%-(48,65%+8,11%)=%O
%O=43,24%